ZTRSYL(3F)ZTRSYL(3F)NAME
ZTRSYL - solve the complex Sylvester matrix equation
SYNOPSIS
SUBROUTINE ZTRSYL( TRANA, TRANB, ISGN, M, N, A, LDA, B, LDB, C, LDC,
SCALE, INFO )
CHARACTER TRANA, TRANB
INTEGER INFO, ISGN, LDA, LDB, LDC, M, N
DOUBLE PRECISION SCALE
COMPLEX*16 A( LDA, * ), B( LDB, * ), C( LDC, * )
PURPOSE
ZTRSYL solves the complex Sylvester matrix equation:
op(A)*X + X*op(B) = scale*C or
op(A)*X - X*op(B) = scale*C,
where op(A) = A or A**H, and A and B are both upper triangular. A is M-
by-M and B is N-by-N; the right hand side C and the solution X are M-by-
N; and scale is an output scale factor, set <= 1 to avoid overflow in X.
ARGUMENTS
TRANA (input) CHARACTER*1
Specifies the option op(A):
= 'N': op(A) = A (No transpose)
= 'C': op(A) = A**H (Conjugate transpose)
TRANB (input) CHARACTER*1
Specifies the option op(B):
= 'N': op(B) = B (No transpose)
= 'C': op(B) = B**H (Conjugate transpose)
ISGN (input) INTEGER
Specifies the sign in the equation:
= +1: solve op(A)*X + X*op(B) = scale*C
= -1: solve op(A)*X - X*op(B) = scale*C
M (input) INTEGER
The order of the matrix A, and the number of rows in the matrices
X and C. M >= 0.
N (input) INTEGER
The order of the matrix B, and the number of columns in the
matrices X and C. N >= 0.
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ZTRSYL(3F)ZTRSYL(3F)
A (input) COMPLEX*16 array, dimension (LDA,M)
The upper triangular matrix A.
LDA (input) INTEGER
The leading dimension of the array A. LDA >= max(1,M).
B (input) COMPLEX*16 array, dimension (LDB,N)
The upper triangular matrix B.
LDB (input) INTEGER
The leading dimension of the array B. LDB >= max(1,N).
C (input/output) COMPLEX*16 array, dimension (LDC,N)
On entry, the M-by-N right hand side matrix C. On exit, C is
overwritten by the solution matrix X.
LDC (input) INTEGER
The leading dimension of the array C. LDC >= max(1,M)
SCALE (output) DOUBLE PRECISION
The scale factor, scale, set <= 1 to avoid overflow in X.
INFO (output) INTEGER
= 0: successful exit
< 0: if INFO = -i, the i-th argument had an illegal value
= 1: A and B have common or very close eigenvalues; perturbed
values were used to solve the equation (but the matrices A and B
are unchanged).
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